5² + (a + 1)5 + (3a + 2) = 0
25 + 5a + 5 + 3a + 2 = 0
8a + 32 = 0
8a = –32
a = –4
Jadi persamaan kuadrat tersebut menjadi
x² + (a + 1)x + (3a + 2) = 0
x² + (–4 + 1)x + (3(–4) + 2) = 0
x² + (–3)x + (–12 + 2) = 0
5² + (a + 1)5 + (3a + 2) = 0
25 + 5a + 5 + 3a + 2 = 0
8a + 32 = 0
8a = –32
a = –4
Jadi persamaan kuadrat tersebut menjadi
x² + (a + 1)x + (3a + 2) = 0
x² + (–4 + 1)x + (3(–4) + 2) = 0
x² + (–3)x + (–12 + 2) = 0
Editor: Azkaa Najmuts Tsaqib