B. –2
C. 2
D. 4
Pembahasan:
x² – 2x – 3 = 0
(x – 3)(x + 1) = 0
(x – 3) = 0 atau (x + 1) = 0
x = 3 x = –1
karena x₁ > x₂, maka x₁ = 3 dan x₂ = –1, sehingga
x₁ – x₂ = 3 – (–1) = 3 + 1 = 4
B. –2
C. 2
D. 4
Pembahasan:
x² – 2x – 3 = 0
(x – 3)(x + 1) = 0
(x – 3) = 0 atau (x + 1) = 0
x = 3 x = –1
karena x₁ > x₂, maka x₁ = 3 dan x₂ = –1, sehingga
x₁ – x₂ = 3 – (–1) = 3 + 1 = 4
Editor: Azkaa Najmuts Tsaqib