s² = r² + t²
s² = 6² + 10²
s² = 36 + 100
s² = 136
s = √136
s = 2√34 cm
L = πr (r + s)
L = 3.14 x 6 (6 + 2√34)
L = 18.84 (6 + 2√34)
L = 113.04 + 37.68√34
L = 37.68 (3 + √34) cm²
Volume = 1/3 πr² t
= 1/3 x 3,14 x 6² x 10
= 1/3 x 3.14 x 36 x 10
= 3.14 x 12 x 10
Volume = 376,8 cm³
d). Diketahui:
r = 7 cm
s = 25 cm
Ditanya: luas permukaan dan volume kerucut ?
Dijawab:
s² = r² + t²
25² = 7² + t²
t² = 25² – 7²
t² = 625 – 49
t² = 576
t = √576
t = 24 cm
L = πr (r + s)
= 3.14 x 7 (7 + 25)
= 21.98 x 32
L = 703,36 cm²