Baca Juga: KUNCI JAWABAN Matematika Kelas 9 Halaman 226 227 228 Latihan 4.2 Tentang Kekongruenan Dua Segitiga
- cara pythagoras
a² + a² = (√32)²
2a² = 32
a² = 32 / 2
a² = 16
a = √16
a = 4
b. panjang sisi = 72
sudut = 45°
- cara perbandingan
s : a = 1 : √2
72 : a = 1 : √2
72 / a = 1 / √2
a = 72 × √2
a = 72√2
- cara pythagoras
72² + 72² = a²
2 × 72² = a²
a² = 72²+2
a = 72√2
c. hipotenusa = 16 cm
sudut = 60°
h : b = 2 : √3
16 : b = 2 : √3
16 / b = 2 / √3
16 × √3 = b × 2
b = 16/2 x √3
b = 8√3 cm
d. tinggi = 17√2
sudut = 30°
- Mencari c
c : t = 1 : √3
c : 17√2 = 1 : √3
c = (17√2 x 1) : √3
c = 17√2 : √3
c = (17/3)√6