Network
Jawaban:
a. AB dan JK = 5m
BC dan KL = 4 m
CD dan LM = 8 m
DE dan MN = 4 m
AE dan JN = 5 m
b. c. KJ = BA = 5 m d. Keliling JKLMN = JK + KL + LM + MN + NJ Luas JKLMN = Luas segitiga JKN + Luas segi empat KLMN = (½ x a x t) + (ML x KL) (Keterangan: tinggi segitiga JKN = 7 – 4 = 3) = (½ x NK x 3) + (8 x 4) = (½ x 8 x 3) + (8 x 4) = 12 + 32
KL = BC = 4 m
LM = CD = 8 m
= 5 m + 4 m + 8 m + 4 m + 5 m
= 26 m
